thomastractorsvc Posted September 2, 2016 Share Posted September 2, 2016 I think you are to far into the weeds with this and getting confused. You can't worry about this unless you have a test bench, and some training on how to set everything up. 1) First you need volume, not mass, of fuel per hour. The density of diesel fuel varies, but 0.85 kg/L is a typical value for #2 diesel. For example 1 kg/h x 1 L/0.85 kg = 1.18 L/h. 2) You need the number of injections per hour. the Mack Diesels are 4-cycle engines; each cylinder has one injection per two revolutions. There are 60 min/h 1 inj/2 rev x rpm x (n cylinders) x 60 min/h gives total injections per hour. For example, the 1 kg/h above might be typical of a small 2 cylinder diesel 1/2 x 2200 x 2 x 60 = 132 000 injections per hour 1.18 L/h /132000 inj/h = 8.9 µL/injection Note that 1 mm³ = 1 µL Quote Robert"I reject your reality and substitute my own." Link to comment Share on other sites More sharing options...
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